384. Shuffle an Array
1. Question
Given an integer array nums
, design an algorithm to randomly shuffle the array. All permutations of the array should be equally likely as a result of the shuffling.
Implement the Solution
class:
Solution(int[] nums)
Initializes the object with the integer array nums.int[] reset()
Resets the array to its original configuration and returns it.int[] shuffle()
Returns a random shuffling of the array.
2. Examples
Example 1:
Input
["Solution", "shuffle", "reset", "shuffle"]
[[[1, 2, 3]], [], [], []]
Output
[null, [3, 1, 2], [1, 2, 3], [1, 3, 2]]
Explanation
Solution solution = new Solution([1, 2, 3]);
solution.shuffle(); // Shuffle the array [1,2,3] and return its result.
// Any permutation of [1,2,3] must be equally likely to be returned.
// Example: return [3, 1, 2]
solution.reset(); // Resets the array back to its original configuration [1,2,3]. Return [1, 2, 3]
solution.shuffle(); // Returns the random shuffling of array [1,2,3]. Example: return [1, 3, 2]
3. Constraints
1 <= nums.length <= 200
- -106 <= nums[i] <= 106
- All the elements of
nums
are unique. - At most 5 104 calls *in total will be made to
reset
andshuffle
.
4. References
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/shuffle-an-array 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
5. Solutions
class Solution {
int[] nums;
int[] shuffle;
Random random;
public Solution(int[] nums) {
this.nums = nums;
random = new Random();
}
public int[] reset() {
return nums;
}
public int[] shuffle() {
shuffle = nums.clone();
for (int i = 0; i < shuffle.length; i++) {
swap(i, random.nextInt(shuffle.length));
}
return shuffle;
}
private void swap(int a, int b) {
int temp = shuffle[a];
shuffle[a] = shuffle[b];
shuffle[b] = temp;
}
}
/**
* Your Solution object will be instantiated and called as such:
* Solution obj = new Solution(nums);
* int[] param_1 = obj.reset();
* int[] param_2 = obj.shuffle();
*/